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Question

Three circles touch one another externally. The tangents at their points of contact meet at a point whose distance from a point of contact is 4. Then the ratio of the area of triangle formed by centers to the sum of the radii of the circles is

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Solution

Let C1,C2 and C3 be the centres of three circles of radii r1,r2 and r3 respectively, then the length, then


From above figure in C1C2C3
C1C2=r1+r2,C2C3=r2+r3,C1C3=r1+r3

Now, area of the trianlge C1C2C3
=Area of (OC2C3+OC1C3+OC1C2)
as OP=OQ=OR=4
Area of C1C2C3=4(r1+r2+r3)

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