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Question

Three circles with centre A, B and C respectively, touch one another as shown in the figure. If A, B and C are collinear and PQ is a common tangent to the two smaller circles, where PQ =4, the area of shaded region is
770465_4e61ee5004e047a68457e2ec01d092d1.png

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Solution

Let radius of three circles be R,r1 and r2 of centre A,B,C.
Let the end point of diameter be QR and tangent point M
QPR=90o (angle in semicircle)
PM=12MQ=2
In PMR
(PM)2+(MR)2=(PR)222+(2r2)2=(PR)24(1+r22)=(PR)2(1)
In PMQ
(PM)2+(MQ)2=(PQ)222+r12=(PQ)2(2)
Adding (1) and (2)
8+4(r21+r22)=(PR)2+(PQ)28+4(r21+r22)=(QR)28+4(r21+r22)=4R2
Area of shaded region =π(R2(r21+r22))=2π

897887_770465_ans_d4d9da5df77045519fa2243b625595e0.png

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