Three closed vessels A, B, and C are at the same temperature and contain gases which obey the Maxwellian distribution of velocities.The vessel A contains only $O_{2}$ ,B only $N_{2}$ and C a mixture of equal quantities of $O_{2}$ and $N_{2}$ .If the average speed of the $N_{2}$ molecules in vessel B is $v_{2}$ and that of oxygen molecules in A is $v_{1}$ , the average speed of $N_{2}$ molecules in C is

\frac{(V_{1} + V_{2})}{2}

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\frac{(V_{1} - V_{2})}{2}

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V_{2}

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\sqrt{(V_{1} V_{2})}

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Solution

The correct option is D $V_{2}$
$v_{a v g} = \sqrt{\frac{8 k T}{π m}}$ (standard result)
Since temp remains same, average velocity of $N_{2}$ molecules in C will depend on temp only and remains same and is $v_{2}$

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Similar questions

Q. Three closed vessels, A, B and C at the same temperature T and contain gases which obey the Maxwellian distribution of velocities. Vessel A contains only

O_{2}

, B only

N_{2}

and C a mixture of equal quantities of

O_{2}

and

N_{2}

. If the average speed of the

O_{2}

molecules in vessel A is

v_{1}

, that of the

N_{2}

molecules in vessel B is

v_{2}

, the average speed of the

O_{2}

molecules in vessel C is

Three closed vessels A, B and C are at the same temperature $T$ and contains gases which obey the Maxwellian distribution of velocities. Vessel A contains only $O_{2}$ , B only $N_{2}$ and C a mixture of equal quantities of $O_{2}$ and $N_{2}$ . If the average speed of the $O_{2}$ molecules in vessel A is $V_{1}$ , that of the $N_{2}$ molecules in vessel B is $V_{2}$ , then the average speed of the $O_{2}$ molecules in vessel C is (where $M$ is the mass of an oxygen molecule)