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Question

Three coins are tossed simultaneously $$150$$ times and it is found that $$3$$ tails appeared $$24$$ times,  $$2$$ tails appeared $$45$$ times , $$1$$ tail appeared $$72$$ times. If three coins are tossed simultaneously at random. Find the probability of getting $$3$$ tails,$$2$$ tails , $$1$$ tail and $$0$$ tail.


Solution

Total no. of outcomes$$=150$$

(i) $$3$$ tails

Favourable outcomes$$=24$$
$$P(E)=\dfrac{24}{150}=\dfrac{4}{15}$$

(ii) $$2$$ tails

Favourable outcomes$$=45$$
$$P(E)=\dfrac{45}{150}=\dfrac{3}{10}$$

(iii) $$1$$ tail

Favourable outcomes$$=72$$
$$P(E)=\dfrac{72}{150}=\dfrac{12}{25}$$

(iv) $$0$$ tail

Favourable outcomes$$=150-(24+45+72)=150-141=9$$
$$P(E)=\dfrac 9{150}=\dfrac 3 {50}$$.

Mathematics

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