Three coins are tossed simultaneously $200$ times with the following frequencies of different outcomes:
Outcome $3 h e a d s$ $2 h e a d s$ $1 h e a d$ No head
Frequency $23$ $72$ $77$ $28$
If the three coins are simultaneously tossed again, compute the probability of $2$ heads coming up.

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Solution

A = event that $2$ heads come up while tossing 3 coins simultaneously.

Number of times 2 heads come up $= 72$ ....given

Total number of times the coins were tossed $= 200$ ...given

Probability $= \frac{Number of times 2 heads come up}{Total number of times the coins were tossed}$

$= \frac{72}{200} = \frac{9}{25}$

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Similar questions

Outcome	3 heads	2 heads	1 head	No head
Frequency	23	72	77	28

\begin{matrix} O u t c o m e & 3 h e a d s & 2 h e a d s & 1 h e a d & N o h e a d F r e q u e n c y & 23 & 72 & 77 & 28 \end{matrix}

Three coins are tossed simultaneously $200$ times with the following frequencies of different outcomes:

Outcome	$3$ heads	$2$ heads	$1$ head	No head
Frequency	$23$	$72$	$77$	$28$

If the three coins are simultaneously tossed again, compute the probability of $2$ heads coming up.

Two coins are tossed simultaneously $1000$ times with the following frequencies at different outcomes

$\begin{matrix} Overhead & Frequency 2 heads & 350 1 head & 310 No head & 340 \end{matrix}$

if these two coins are tossed again, find the probability of getting

(i) at least 1 head

(ii) at most one head

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Outcome	$3 h e a d s$	$2 h e a d s$	$1 h e a d$	No head
Frequency	$23$	$72$	$77$	$28$