Question

Three coins are tossed simultaneously. Find the probability of getting three heads.

Answer 1

Finding the probability of getting three heads.

Let $\text{P}\left(\text{E}\right)$ be the probability of getting three heads.

All possible outcomes when three coins are tossed simultaneously$=\text{HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}$

$\therefore$Number of possible outcomes$=8$

Outcomes having three heads$=\text{HHH}$

$\therefore$Number of favourable outcomes$=1$

We know that $\text{P}\left(\text{E}\right)\text{=}\frac{\text{Number of favourable outcomes}}{\text{Number of possible outcomes}}$

So, $\text{P}\left(\text{E}\right)$$=\frac{1}{8}$

Hence, probability of getting three heads$=\frac{\mathbf{1}}{\mathbf{8}}$