Question

Three coins are tossed together. Find the probability of getting utmost two heads

Answer 1

The possible outcomes when three coins are tossed together are

{$HHH,TTT,THT,TTH,HHT,HTH,THH,HTT$}. Therefore, the number of possible outcomes when two coins are tossed is $8$.

Now, the possible outcomes of getting at most one head are {$TTT,TTH,THT,HTT,THH,HTH,HHT$}, which means the number of favourable outcome is $7$.

Therefore, probability $P$ of getting at most one head is:

$P=\frac{7}{8}$

Hence, the probability of getting at most one head is $\frac{7}{8}$.