Three coins are tossed together, then the probability of getting at least one head is-

\frac{1}{2}

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\frac{3}{4}

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\frac{1}{8}

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\frac{7}{8}

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Solution

The correct option is D $\frac{7}{8}$
$\begin{matrix} T h e p o s s i b l e o u t c o m e s {T T T, H H H, T H T, T T H, H T T, H T H, T H H, H H T} T h e n p r o b a b i l i t y o f g e t t i n g a t l e a s t o n e h e a d P = \frac{7}{8} \end{matrix}$

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