Three coins are tossed. What is the probability of getting 2 Tails and 1 Head?

\frac{1}{2}

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\frac{3}{8}

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\frac{2}{3}

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\frac{3}{4}

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Solution

The correct option is B $\frac{3}{8}$
$W h e n t h r e e c o i n s a r e t o s s e d w e g e t$

HHH or (1)
HHT or (2)
HTT or (3)
HTH or (4)
THH or (5)
THT or (6)
TTT or (7)
TTH or (8)

$W e g e t 2 T a n d 1 H i n 3 c a s e s$

$S o p r o b a b i l i t y = \frac{3}{8}$

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