Question

Three coins each 2 cm in diameter are placed touching one another. Find the area enclosed by them.

Answer 1

Area required=area of $△ABC-3\times$area of $1$ quadrant

$=\frac{\sqrt{3}}{4}\times {\left(2\right)}^2-3\times \frac{60}{360}\times \frac{22}{7}\times 1\times 1$

$=\sqrt{3}-\frac{11}{7}$

$=\frac{12.12-11}{7}=0.16㎠$