Three companies are bidding on a contract. Company A is twice as likely to win as Company B, and Company B is three times as likely to win as Company C. What is the probability of company A winning the contract?

0.1

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0.6

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0.5

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Solution

The correct option is B
0.6

Let the probability of C winning be p.

Then the probability of B winning = 3p.

The probability of A winning = 6p.

We know that the sum of probabilities is 1. That is,

p + 3p + 6p = 10p = 1

p = 0.1

Thus, P (A) = 6 × 0.1 = 0.6

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Three companies are bidding on a contract. Company A is twice as likely to win as Company B, and Company B is three times as likely to win as Company C. What is the probability of company A winning the contract?

The correct option is B 0.6 Let the probability of C winning be p. Then the probability of B winning = 3p. The probability of A winning = 6p. We know that the sum of probabilities is 1. That is, p + 3p + 6p = 10p = 1 p = 0.1 Thus, P (A) = 6 × 0.1 = 0.6

The correct option is B
0.6

Let the probability of C winning be p.

Then the probability of B winning = 3p.

The probability of A winning = 6p.

We know that the sum of probabilities is 1. That is,

p + 3p + 6p = 10p = 1

p = 0.1

Thus, P (A) = 6 × 0.1 = 0.6