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Question

Three concentric conducting spherical shells of radii R,2R and 3R carry charges Q,2Q and 3Q, respectively. Compute the electric field at r=52R.
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A
+Q25πε0R2ˆr
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B
Q25πε0R2ˆr
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C
Q5πε0R2ˆr
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D
+Q5πε0R2ˆr
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Solution

The correct option is B Q25πε0R2ˆr

There will be no electric field inside the metallic sphere due to the charge present on its either inner or outer surface.

Inside the metallic sphere, hence electric field will only be present due to the charge present at the center. Therefore, field at a point r=5R/2 inside the outer sphere and outside the inner two spheres, field is due to the net charge on sphere of radius R and 2R. Therefore field is

14πϵoQ2Q25R2/4=125πϵ0QR2


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