Three concurrent forces F1 F2 and F3 nbsp-are in equlibrium-if f1-3N nbsp-f2-4N and f1 and f2 r perpendicular find magnitude of F3

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Standard XII

Physics

Newton's Second Law: Rotatory Version

three concurr...

Question

three concurrent forces F1 F2 and F3 are in equlibrium.if f1=3N f2=4N and f1 and f2 r perpendicular find magnitude of F3

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Solution

Dear Student ,
Three forces are said to be concurrent and also if they are in equilibrium then ,
${\vec{F}}_{1} + {\vec{F}}_{2} = \vec{F_{3}} \Rightarrow \vec{F_{3}} = 3 + 4 = 7 N$
Regards

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Similar questions

Q. If

F_{1}

F_{2}

makes an angle of

30^{\circ}

and

45^{\circ}

respectively with

F_{3}

as shown in the figure, and magnitude of

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_{1} +_{2} =_{3}

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Q. If

F_{1}

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Statement I:

If three forces

_{1},_{2}

and

_{3}

are represented by three sides of a triangle and

_{1} +_{2} = -_{3}

, then these forces are concurrent forces and satisfy the condition for equilibrim.

Statement II :

A triangle made up of three forces

_{1},_{2}

and

_{3}

as its sides taken in the same order, satisfy the condition for translatory equilibrium.

In the light of the above statements, choose the most appropriate answer from options given below.

The centre of an equilateral triangle is O. Three forces F1,F2 and F3 are appointed along AB, BC and AC respectively. The magnitude of F3 so that the total torque about O should be zero is

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three concurrent forces F1 F2 and F3 are in equlibrium.if f1=3N f2=4N and f1 and f2 r perpendicular find magnitude of F3

Dear Student , Three forces are said to be concurrent and also if they are in equilibrium then , F→1+F→2=F3→⇒F3→=3+4=7N Regards

Dear Student ,
Three forces are said to be concurrent and also if they are in equilibrium then ,
${\vec{F}}_{1} + {\vec{F}}_{2} = \vec{F_{3}} \Rightarrow \vec{F_{3}} = 3 + 4 = 7 N$
Regards