Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces ? Also name the triangle formed by the forces as sides

60° equilateral triangle

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120° equilateral triangle

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120°, 30°, 30° an isosceles triangle

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120° an obtuse angled triangle

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Solution

The correct option is A 60° equilateral triangle
In N forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given
$θ$ = $\frac{360}{N}$ = $\frac{360}{3}$ = $120^{\circ}$

If these threee vectors are represented by three sides of triangle then they form equilateral triangle

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