Question

Three condensers each of capacitance 2 F, are connected in series. The resultant capacitance will be :

• A. 6 F
• B. 5 F
• C. 2/3 F
• D. 3/2 F

Answer 1

Answer: (C)

2/3 F

Let the resultant capacitor is $C_R$
For series combination of three capacitors , $\frac{1}{C_R}=\frac{1}{C}+\frac{1}{C}+\frac{1}{C}=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}=\frac{3}{2}$ F
$\therefore C_R=\frac{2}{3}F$