Question

three consecutive even numbers have a sum of 24 . find their product

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}3\mathrm{consecutive}\mathrm{even}\mathrm{numbers}\mathrm{be}\mathrm{x},\mathrm{x}+2\mathrm{and}\mathrm{x}+4. \\ \mathrm{Now},\mathrm{x}+\mathrm{x}+2+\mathrm{x}+4=24 \\ \Rightarrow 3\mathrm{x}+6=24 \\ \Rightarrow 3\mathrm{x}=24-6 \\ \Rightarrow 3\mathrm{x}=18 \\ \Rightarrow \mathrm{x}=\frac{18}{3}=6 \\ \mathrm{So},\mathrm{consecutive}\mathrm{even}\mathrm{numbers}\mathrm{are}: \\ 6,8,10 \\ \mathrm{Now},\mathrm{product}=6\times 8\times 10=480 \end{gathered}$$