Question

Three consecutive integers are such that four times the least integer is three times the greatest. Find the greatest of these three integers.

• A. $6$
• B. $8$
• C. $10$
• D. $12$

Answer 1

The correct option is B $8$

Let the $3$ consecutive number be $k,k+1,k+2$
According to question:
$4k=3(k+2)\Rightarrow 4k=3k+6\Rightarrow 4k-3k=6\Rightarrow k=6$
The greatest integer is $k+2=8$.