Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively, they add up to 74. Find these numbers.
A
Numbers are 6,5 and 10
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B
Numbers are 7,8 and 9
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C
Numbers are 3,3 and 5.
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D
Numbers are 9,16 and 19
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Solution
The correct option is B Numbers are 7,8 and 9 Let the three consecutive integers be x,(x+1) and (x+2).
According to the given condition, we have 2×x+3×(x+1)+4×(x+2)=74⇒2x+3x+3+4x+8=74⇒9x+11=74⇒9x=74−11⇒9x=63⇒x=639=7
Hence, other numbers are x+1=7+1=8 and x+2=7+2=9. Hence, the numbers are 7,8 and 9.