Question

Three consecutive positive integers are such that the sum of the square of the first and the product of the other two is 46. Find the integers.

Answer 1

Let the numbers are x,x+1,x+2.
As per the question,
$x^2+(x+1)(x+2)=46$
i.e. $2x^2+3x-44=0$
Now, By applying quadratic formula, we get
x = -22/4, 4.
But x can't be negative.
So, Numbers will be 4,5 and 6