Question

Three consecutive positive integers are such that the sum of the square of the first and the product of other two is 46, find the integers,

Answer 1

Let the three consecutive integers be (x-1), x and (x+1).

Now according to the question,

As it is given that the integer is positive hence x=5.

Thus the required integers are (5-1), 5 and (5+1), that is 4, 5 and 6.