Three consecutive whole numbers are such that if they be divided by 5, 3 and 4 respectively; the sum of the quotients is 40. Find the numbers.
Let the three consecutive whole numbers be x, x+1 and x+2
According to the statement :
x5+x+13+x+24=40⇒ x5×60+x+13×60+x+24×60=40×60
[Multiplying each term by 60 because L.C.M. of denominators = 60]
⇒ 12x+20(x+1)+15(x+2)=2400⇒ 12x+20x+20+15x+30=2400⇒ 12x+20x+15x=2400−20−30⇒ 47x=2350⇒ x=235047⇒ x=50∴ x+1=50+1=51 x+2=50+2=52
∴ Three consecutive whole numbers are 50, 51 and 52