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Work Done When Force Is Varying

Three constan...

Question

Three constant forces F1 = 2i-3j+2k, F2 = i+j-k, and F3 = 3i+j-2k in newtons displace a particle from (1, -1, 2) to (-1, -1, 3) and then to (2, 2, 0) (displacement being measured in meteres). Find the total work done by the forces.

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Solution

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_{1} = 2^i - 3^j + 2^k,_{2} =^i +^j -^k

_{3} =^j - 2^k

(1, - 1, 2)

(- 1, - 1, 3)

(2, 2, 0)

_{1} = (2^i - 3^j + 2^k) N,_{2} = (^i +^j -^k) N

_{3} = (3^i +^j - 2^k) N

(1, - 1, 2) m

(- 1, - 1, 3) m

(2, 3, 4) m

_{1} = (2^i - 3^j + 2^k) N,_{2} = (^i +^j -^k) N

_{3} = (3^i +^j - 2^k) N

(1, - 1, 2) m

(- 1, - 1, 3) m

(2, 3, 4) m

_{1} = (2^i - 4^j) N

(1, - 1, 2)

(- 1, - 1, 3)

_{2} = (3^i + 4^j) N

(- 1, - 1, 3)

(5, 5, 5)

_{1} = (2^i - 4^j) N

(1, - 1, 2)

(- 1, - 1, 3)

_{2} = (3^i + 4^j) N

(- 1, - 1, 3)

(5, 5, 5)

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