Question

Three containers have their volumes in ratio 3:4:5. They are full of mixtures of milk and water in the ratio of (4:1),(3:1) and (5:2) respectively . The ratio of milk and water in the fourth container contains all the above three mixtures is=

Options....

(1.)4:1. (2.)151:48

(3.)157:53. (4.)5:2

Answer 1

Let the three containers contain 3x, 4x and 5x liters of mixtures respectively. (or consider x=1)
Milk in 1st container = (4/5) * 3x = (12x)/5
Water in 1st container = 3x - (12x/5) = (3x)/5
Milk in 2nd container = (3/4) * 4x = 3x
Water in 2nd container = 4x - 3x = x
Milk in 3rd container = (5/7) * 5x = (25x)/7
Water in 3rd container = 5x - (25x/7) = (10x)/7

Therefore, total milk = (12x)/5 + 3x + (25x)/7 = (314x)/35
Total water = (3x)/5 + x + (10x)/7 = (21x + 35x + 50x)/35 = (106x)/35

So, ratio of milk and water in the fourth container = (314x)/35 : (106x)/35 = 314 : 106 = 157 : 53

answer is option C