Three containers have their volumes in the ratio $3 : 4 : 5 .$ They are full of mixtures of milk and water. The mixtures contain milk and water in the ratio of $(4 : 1), (3 : 1)$ and $(5 : 2)$ respectively. The ratio of milk and water in the fourth container which contains mixture of all the above three mixtures is

4 : 1

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151 : 48

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157 : 53

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5 : 2

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Solution

The correct option is B

$157 : 53$
Let the three containers contain $3 x, 4 x a n d 5 x$ litres of mixtures respectively. Milk in 1st mixture
$= (3 x \times \frac{4}{5}) l i t r e s = \frac{12 x}{5} l i t r e s .$
Water in 1st mixture
$= (3 x - \frac{12 x}{5}) l i t r e s = \frac{3 x}{5} l i t r e s .$
Milk in 2nd mixture = $(4 x \times \frac{3}{4})$ litres = 3x litres
Water in 2nd mixture = (4x - 3x) litres = x litres.
Milk in 3rd mixture = $(5 x \times \frac{5}{7}) l i t r e s = \frac{25 x}{7}$
Water in 3rd mixture
= $(5 x \times \frac{25 x}{7}) l i t r e s = \frac{10 x}{7} l i t r e s$
Total milk in final mixture =
$(\frac{12 x}{5} + x + \frac{25 x}{7}) l i t r e s = \frac{314 x}{35}$ litres. Total water in final mixture
= $(\frac{3 x}{5} + x + \frac{10 x}{7}) l i t r e s = \frac{106 x}{35}$ litres. Required ratio of milk and water = $\frac{314 x}{35} : \frac{106 x}{35} = 157 : 53$

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Three containers have their volumes in ratio 3:4:5. They are full of mixtures of milk and water in the ratio of (4:1),(3:1) and (5:2) respectively . The ratio of milk and water in the fourth container contains all the above three mixtures is=

Options....

(1.)4:1. (2.)151:48

(3.)157:53. (4.)5:2

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Three containers have their volumes in the ratio 3:4:5. They are full of mixtures of milk and water. The mixtures contain milk and water in the ratio of (4:1),(3:1) and (5:2) respectively. The ratio of milk and water in the fourth container which contains mixture of all the above three mixtures is