Question

Three containers have their volumes in the ratio $3:4:5$. They are full of mixtures of milk and water. The mixtures contain milk and water in the ratio of $(4:1),(3:1)$ and $(5:2)$ respectively. The contents of all these three containers are poured into a fourth container. The ratio of milk and water in the fourth container is-

• A. $4:1$
• B. $151:48$
• C. $157:53$
• D. $5:2$

Answer 1

The correct option is C $157:53$

Ratio of volume of mixture in three containers $=3:4:5$

Let the volume of mixture in three containers be $3x,4x$ and $5x$

$Milk:Water$

$1^{st}container=4:12^{nd}container=3:13^{rd}container=5:2$

$in$ $4^{th}container:$

$\frac{Milk}{Water}=\frac{\frac{4}{5}\times 3x+\frac{3}{4}\times 4x+\frac{5}{7}\times 5x}{\frac{1}{5}\times 3x+\frac{1}{4}\times 4x+\frac{2}{7}\times 5x}=\frac{\frac{12x}{5}+\frac{12x}{4}+\frac{25x}{7}}{\frac{3x}{5}+\frac{4x}{4}+\frac{10x}{7}}=\frac{\frac{336x+420x+500x}{140}}{\frac{84x+140x+200x}{140}}=\frac{1256}{424}=\frac{157}{53}$