Three cubes each of side $5 c m$ are joined end to end. Find the surface area of the resulting cuboid.

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Solution

The dimensions of the cuboid so formed are as under:

$l =$ length $= 15 c m$ , $b =$ breadth $= 5 c m$ , $h =$ height $= 5 c m$

Surface area of the cuboid $= 2 (15 \times 5 + 5 \times 5 + 15 \times 5) {c m}^{2}$

$= 2 (75 + 25 + 75) {c m}^{2} = 350 {c m}^{2}$

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