Question

Three cubes each of volume 125 cm³ are joined end-to-end to form a cuboid. Find the total surface area of cuboid.

Answer 1

Let the edge of each cube be $a$
As,Volume of each cube$=125c{m}^3$

$\Rightarrow a^3=125$

$\Rightarrow a=5cm$

So, the length of the cuboid,

$l=3a=3\times 5=15cm,$

the breadth of the cuboid, $b=5cm$

And the height of the cuboid, $h=5cm$

Now,Total surface area of the cuboid

$=2(lb+bh+hl)$

$=2(15\times 5+5\times 5+5\times 15)$

$=2(75+25+75)$

$=2\times 175$

$=350c{m}^2$
So, the total surface area of the cuboid so formed is 350 cm².