Three cubes of metal with edge 3 cm, 4 cm and 5 cm respectively are melted to form a single cube. Find the lateral surface area of the new cube formed.

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Solution

Dear student,

$E d g e s o f 3 c u b e s a r e : 3 c m, 4 c m a n d 5 c m S o, V o l u m e o f t h e b i g g e r c u b e = V o l u m e o f 3 c u b e s a^{3} = 3^{3} + 4^{3} + 5^{3} \Rightarrow a = 6 c m N o w, L a t e r a l s u r f a c e a r e a o f t h e n e w c u b e = 6 a^{2} = 6 * 6^{2} = 216 c m^{2}$

Regards

$E d g e s o f 3 c u b e s a r e : 3 c m, 4 c m a n d 5 c m S o, V o l u m e o f t h e b i g g e r c u b e = V o l u m e o f 3 c u b e s a^{3} = 3^{3} + 4^{3} + 5^{3} \Rightarrow a = 6 c m N o w, L a t e r a l s u r f a c e a r e a o f t h e n e w c u b e = 6 a^{2} = 6 * 6^{2} = 216 c m^{2}$

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