Three cubes of side 4 cm each, are joined end to end. The TSA of the resultant cuboid is ___ sq. cm.
224

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Solution

The correct option is A 224

Dimensions of the cuboid formed :

Length, $l = 12 c m$
Breadth, $b = 4 c m$
Height, $h = 4 c m$

Total surface area of the cuboid formed $= 2 (l \times b + b \times h + l \times h)$

$= 2 (12 \times 4 + 4 \times 4 + 4 \times 12)$

$= 2 (48 + 16 + 48)$

$= 2 \times 112 = 224 c m^{2}$

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