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Question
Three cubes of side a are joined end to end .What is the surface area of the new solid thus formed?
Three cubes of side a are joined end to end .What is the surface area of the new solid thus formed?
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Solution
The correct option is D 14a3
The resulting solid will be a cuboid of length 3a, width a and height a.
Thus, Surface Area = 2(lb + bh + lh)
= 2[(3a)(a) + (a)(a) + (3a)(a)]
= 2[3a2 + a2 + 3a2]
= 2(7a2)
= 14a2
14a3
The resulting solid will be a cuboid of length 3a, width a and height a.
Thus, Surface Area = 2(lb + bh + lh)
= 2[(3a)(a) + (a)(a) + (3a)(a)]
= 2[3a2 + a2 + 3a2]
= 2(7a2)
= 14a2
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