Question

Three cups of ice cream, two burgers and four soft drinks together cost $Rs.128$. Two cups of ice cream, one burger and two soft drinks together cost $Rs.74$. What is the cost of five burgers and ten soft drinks?

• A. $160$
• B. $170$
• C. Cannot be determined
• D. $128$

Answer 1

The correct option is B $170$

Let cost of each ice cream, burger and soft drinks is $x,y$ and $z$ respectively.
$3x+2y+4z=\mathrm{128....}\left(i\right)$
$2x+y+2z=\mathrm{74...}\left(ii\right)$
Multiply $3\times \left(ii\right)$ and $2\times \left(i\right)$, we get

$6x+2y+6z=\mathrm{222....}\left(iii\right)$
$6x+4y+8z=256)....(iv)$

Substract equation $\left(iv\right)$ to equation $\left(iii\right)$
$y+2z=34$
Multiply the avbove equation by $5$
we get,
$5(y+2z)=5\times 34$
$5y+10z=170$
$\therefore$ Cost of $5$ burgers and $10$ soft drinks $=34\times 5=170$