Question

three dice are thrown simultaneously. find the probability of getting a total of atleast 6.

Answer 1

Number of events of getting a total of 6 = 10

i.e. (1, 1, 4), (1, 4, 1), (4, 1, 1), (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1) and (2, 2, 2).

Therefore, probability of getting a total of 6

Number of favorable outcomes
P(E₄) = Total number of possible outcome

= 10/216
= 5/108