Question

Three different coins are tossed together. Find the probability of getting
(i) exactly two heads

Answer 1

Given:

Here, three different coins are tossed together at a time.

Find the sample space:

Sample space$=\left\{HHH,HHT,HTH,THH,TTH,THT,HTT,TTT\right\}$

$\therefore$Total no. of outcomes$=8$

Find the favourable outcomes:

Here, Favourable outcomes $=\left\{HHT,HTH,THH\right\}$

$\therefore$No. of favourable outcomes $=3$

Let $E$ be the event of getting exactly two heads.

Find the probability:
$Probability=\frac{Totalno.offavorableoutcomes}{Totalno.ofpossibleoutcomes}$

$\therefore P\left(E\right)=\frac{3}{8}$

Final answer: Hence, the probability of getting exactly two head is $\frac{\mathbf{3}}{\mathbf{8}}$.