Question

Three different integers are randomly selected from a group of five unique integers consisting of 1 through 5. What is the probability that these numbers are 1, 2, and 3?

• A. One in five
• B. One in ten
• C. One in twenty
• D. One in sixty

Answer 1

Answer: (B)

One in ten

Total Possibilities = ${}^5{C}_3=\frac{5!}{(3!)(2!)}=10$

As three integers are selected hence to obtain numbers 1, 2 and 3, there is only one possibility.

Hence, the probability that these numbers are 1, 2, and 3 = $\frac{1}{10}$