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Question

Three discs A,B,C having radii 2 m, 4 m and 6 m respectively are coated with carbon black on their outer surface. The wavelengths corresponding to the maximum intensity for each of them are 300 nm,400 nm,500 nm respectively. The power radiated by the discs are QA,QB and QC respectively. Then,

A
QA is maximum
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B
QB is maximum
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C
QC is maximum
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D
QA=QB=QC
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Solution

The correct option is B QB is maximum
According to Stefan boltzmann law
Q=σAT4, Here A=πr2

According to wien's law
λmT=b
or, T=(bλm)Q=σ(πr2)(bλm)4
Qr2λ4m

QA223004

QB424004

QC625004

QB>QC>QA

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