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Question

Three discs,a, b,c having radii 2m,4m,6m respectively are coated with carbon black on their outer surface the wavelength corresponding to maximum intensity are 300,400,500nm respectively the power radiated by them are QA,QB,​​​​​​,Qc
Opts-

Qa is max
Qbis max
Qc is max
Qa=Qb=Qc

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Solution

according to Wein's displacement law λT = constant

so ratio of temperatures of the three discs will be 1/3:1/4:1/5 = 20:15:12

and ratio of area of the discs = 1:4:9

now according to Stephan's law Q α A * T4

so ratio Qa:Qb:Qc = 1*(20)4 : 4*(15)4 : 9*(12)4

on solving we will get that Qb is maximum


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