Question

Three elements A, B and C crystallize in an FCC lattice. Atoms A occupy the corners and the face centres whereas atoms B are present at the cube centres and C atoms at the edges centres. If the simple formula of the compound is $A_x{B}_y{C}_z$. What is the value of $(x+y+z)$?

Answer 1

$x=8\times \frac{1}{8}+6\times \frac{1}{2}=4$

$y=1$

$z=12\times \frac{1}{4}=3$

$\therefore x+y+z=8$