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Question

Three equal charges, each having a magnitude of 4μC , are placed at the three corners of a right-angled triangle of sides 6cm,8cm and 10cm. The force on the charge at the right-angle corner will be

A
11.5N
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B
23N
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C
46N
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D
230N
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Solution

The correct option is A 11.5N

Two forces are,

F1=kQ1Q2R12

=9×109×(4×106)2(6×102)2

=10N

F2=kQ1Q2R22

=9×109×(4×106)2(8×102)2

=36064=5.62N

Resultant force at the right angle vertex is,

F=(F12+F22)

=102+5.622

=131.56

=11.5N


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