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Question

Three equal masses each of mass m are placed at the three-corners of an equilateral triangle of side a.
If a fourth particle of equal mass is placed at the centre of triangle, then the net force acting on it, is equal to:

A
Gm2a2
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B
4Gm23a2
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C
3Gm2a2
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D
Zero
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Solution

The correct option is C 3Gm2a2
cos30o=a/2r
r=a2cos30o=a3
|F|oneparticle=Gm2r2=3Gm2a2


981488_1079547_ans_3eebe6cda5194505a017572cddf080dd.png

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