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Byju's Answer
Standard XII
Physics
Pendulum in Non Inertial Frame
Three equal p...
Question
Three equal point masses of 1.5kg each are fixed at the vertices of equilateral triangle of side 1 m. What is the force acting on a particle of mass 1 kg place at its centroid
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Similar questions
Q.
Three equal masses of m kg each are fixed at the vertices of an equilateral triangle ABC.
a. What is the force acting on a mass
2
m placed at the centroid G of the triangle?
b. What is the force if the mass at the vertex A is doubled? Take AG
=
BG
=
CG
=
1
m.
Q.
Three equal masses of
1
kg
each are placed at the vertices of an equilateral triangle
PQR
and a mass of
2
kg
is placed at the centroid
O
of the triangle which is at a distance of
√
2
m
from each of the vertices of the triangle. The net force (in Newton), acting on the mass of
2
kg
is
Q.
Three equals masses of
m
k
g
each are fixed at the vertices of an equilateral triangle
A
B
C
, a shown in Fig.
8.10
.
(a) What is the force acting on a mass
2
m
placed at the centroid
G
of the triangle?
(b) What is the force if the mass at the vertex
A
is doubled?
Take
A
G
=
B
G
=
C
G
=
1
m
Q.
Three equal masses each of mass
m
are placed at the three-corners of an equilateral triangle of side a.
If a fourth particle of equal mass is placed at the centre of triangle, then the net force acting on it, is equal to:
Q.
Three masses each of mass m are placed at the vertices of an equilateral triangle ABC of side l as shown in the figure. The force acting on a mass 2m placed at the centroid O of the triangle is:
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