Three equal resistance each of 10 ohm are connected (2 in parallel, and 1 in series). The maximum safe power consumed by each resistor is 20W. The maximum safe power consumed by the combination is?

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Solution

Effective resistance of 2 parallel resistors are
R=R1R2/(R1+R2)
=100/20
=5

Then there is 2 resistors of 5&10 in series,their effective resistance,R=R1+R2
=5+10
=15
now we know

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Three equal resistance each of 10 ohm are connected (2 in parallel, and 1 in series). The maximum safe power consumed by each resistor is 20W. The maximum safe power consumed by the combination is?

Effective resistance of 2 parallel resistors are R=R1R2/(R1+R2) ​​​​​​ =100/20 =5 Then there is 2 resistors of 5&10 in series,their effective resistance,R=R1+R2 =5+10 =15 now we know

Effective resistance of 2 parallel resistors are
R=R1R2/(R1+R2)
=100/20
=5

Then there is 2 resistors of 5&10 in series,their effective resistance,R=R1+R2
=5+10
=15
now we know