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Question

Three equal resistors connected in series across a source of emf together dissipate 10W of power. What should be the power dissipated if the same resistors are connected in parallel across the same source of emf?

A
9W
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B
90W
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C
10W
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D
100W
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Solution

The correct option is B 90W
Case 1:- (When connected in series)
Rnet=R+R+R=3R
Power dissipated$=\cfrac{V^{2}}{R_{net}}=\cfrac{V^{2}}{3R}=10W
V2R=30W

Case 2:-(When connected in parallel)
Rnet=R3
Power dissipated=V2Rnet(Case2)=3(V2R)
=3×30W=90W

Figure1 represents Case 1.
Figure 2 represents Case 2.

1102222_1016665_ans_dfd513d2f3bb4047833a63b9b0517b83.png

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