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Question

# Three equal resistors connected in series across a source of emf together dissipate 10W of power. What should be the power dissipated if the same resistors are connected in parallel across the same source of emf?

A
9W
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B
90W
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C
10W
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D
100W
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Solution

## The correct option is B 90WCase 1:- (When connected in series)Rnet=R+R+R=3RPower dissipated\$=\cfrac{V^{2}}{R_{net}}=\cfrac{V^{2}}{3R}=10WV2R=30WCase 2:-(When connected in parallel)Rnet=R3Power dissipated=V2Rnet(Case2)=3(V2R)=3×30W=90WFigure1 represents Case 1.Figure 2 represents Case 2.

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