Three equal resistors connected in series across a source of emf together dissipate 5watt of power. If the same resistors are connected in parallel across the same source of emf, the power dissipated will be
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Solution
When the three resistors are in series, effective resistance in the circuit = 3R. Power dissipated in the series circuit = Pseries = V^2/(3R) = 5 W ⇒ V^2/(R) = 15W When the three resistors are in parallel, effective resistance in the circuit = R/3. Power dissipated in the parallel circuit = Pparallel = V^2/(R/3) = 3V^2/(R) = 3 x 15 W = 45 W