Three equal weights of mass 2kg each are hanging by a string passing over a fixed pulley. The tension in the string (in N) connecting B and C is
A
4g3
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B
g3
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C
2g3
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D
g2
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Solution
The correct option is A4g3 The given system is reframed as shown below
The FBDs of the blocks are as shown
So, we have equation of force as For AT1−2g=2a For BT2+2g−T1=2a For C2g−T2=2a Adding all three equations together, we get 2g=6a⇒a=g3 ∴ Tension in the string connecting B and C is T2=2(g−a)=2×2g3=4g3N