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Question

Three equal weights of mass 2 kg each are hanging by a string passing over a fixed pulley. The tension in the string (in N) connecting B and C is


A
4g3
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B
g3
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C
2g3
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D
g2
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Solution

The correct option is A 4g3
The given system is reframed as shown below


The FBDs of the blocks are as shown


So, we have equation of force as
For A T12g=2a
For B T2+2gT1=2a
For C 2gT2=2a
Adding all three equations together, we get
2g=6a a=g3
Tension in the string connecting B and C is
T2=2(ga)=2×2g3=4g3 N

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