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Question

Three equals masses of m kg each are fixed at the vertices of an equilateral triangle ABC, a shown in Fig. 8.10.
(a) What is the force acting on a mass 2m placed at the centroid G of the triangle?
(b) What is the force if the mass at the vertex A is doubled?
Take AG=BG=CG=1 m
1107042_4134cfea4ead400aa04ecbc9015dbf3e.PNG

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Solution

R.E.F image
a) As the mass of A,B and C are equal and they are equidistant from G.So,
FA=FB=FC=F=G(2m)(m)(1)2
F=2Gm2
Fnet on 2m=FA+FB+FC
=0N

b) As mA=2mB=2mC=2m,
FA=2FB=2FC=G(2m)(2m)12
F=2Gm2
Fnet on 2matG=FA+FB+FC
|Fnet|=F=2Gm2
Fnet=Fj=2GHj

1113766_1107042_ans_7428c81339a447a0bcbd6c43e3b6fc39.jpg

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