Question

Three exterior angles of a hexagen are ${40}^{\circ },{51}^{\circ }$ and ${86}^{\circ }$. If each of the remaining exterior angles are $x^{\circ }$, then x = ___.

• A. 36°
• B. 54°
• C. 18°
• D. 44°

Answer 1

The correct option is B

54°

A hexagen has 6 exterior anlges

We know, sum of exterior angles $={360}^{\circ }$

$40+51+86+3x^{\circ }=360$

$177+3x={360}^{\circ }$

$3x={183}^{\circ }$

$x={61}^{\circ }$