Question

Three faces of a fair dice are yellow, two faces red and one blue. The die is tossed 3 times . The probability that the colours, red and blue appears in the first, second & third tosses respectively is expressed as 1/x.
The square root of x is

Answer 1

Odds of getting yellow on the first throw $=\frac{3}{6}=\frac{1}{2}$
Odds of getting red on the second throw $=\frac{2}{6}=\frac{1}{3}$
Odds of getting blue on the third throw $=\frac{1}{6}$
Therefore required probability $=\frac{1}{2}\times \frac{1}{3}\times \frac{1}{6}=\frac{1}{36}$
$\therefore \sqrt{x}=6$