Question

Three faces of a fair dice are yellow, two faces red and one blue. The die is tossed 3-times. The probability that the colours yellow, red and blue appear in the first, second and the third tosses respectively is .............

• A. $1/36$
• B. $1/216$
• C. $1/72$
• D. $1/108$

Answer 1

The correct option is A $1/36$

According to given condition
$P$(yellow at the first toss) $=\frac{3}{6}=\frac{1}{2}$

$P$(red at the second toss) $=\frac{2}{6}=\frac{1}{3}$
and $P$(blue at the third toss) $=\frac{1}{6}$
Therefore, the probability of the required event $=\frac{1}{2}\times \frac{1}{3}\times \frac{1}{6}=\frac{1}{36}$