Question

Three faces of a fair dye are yellow, two faces red and one blue. The die is tossed three times. The probability that the colours, yellow red and blue appear in first, second and the third tosses respectively is ............

• A. $\frac{5}{36}$
• B. 0
• C. $\frac{1}{36}$
• D. 1

Answer 1

The correct option is C

$\frac{1}{36}$

$P\left(Y\right)=\frac{3}{6}$
$P\left(R\right)=\frac{2}{6}$
$P\left(B\right)=\frac{1}{6}$
$\because$ Outcomes are independent in each toss.
$P\left(YRB\right)=P\left(Y\right).P\left(R\right).P\left(B\right)$
$=\frac{3}{6}.\frac{2}{6}.\frac{1}{6}$
$=\frac{1}{36}$