Question

Three fair cubical dice are thrown simultaneously. The probability that all three dice have the same number on the faces showing up is (up to third decimal place)

• A. 0.0278

Answer 1

The correct option is A 0.0278

The total no. of outcomes,
$n\left(s\right)=6\times 6\times 6=216$

The favourable outcomes, n(E) are (1, 1, 1), (2, 2, 2), ..... (6, 6, 6)

So, n(E) = 6

$\therefore$ Required probability $=\frac{n\left(E\right)}{n\left(s\right)}=\frac{6}{216}=0.0278$